Alexandria Bay, New York

Alexandria Bay is a village in Jefferson County, New York, United States, within the town of Alexandria. It is in the Thousand Islands region of northern New York. The population of the village was 924 at the 2020 United States Census.[2]

Boldt Castle 3 db.jpg
 
Coordinates: 44°20′9″N 75°54′53″W / 44.33583°N 75.91472°W / 44.33583; -75.91472Coordinates: 44°20′9″N 75°54′53″W / 44.33583°N 75.91472°W / 44.33583; -75.91472
CountryUnited States
StateNew York
RegionThe Thousand Islands (New York)
CountyJefferson
TownAlexandria
Area
 • Total1.51 sq mi (3.90 km2)
 • Land0.75 sq mi (1.94 km2)
 • Water0.76 sq mi (1.96 km2)
Elevation
284 ft (87 m)
Population
 • Total924
 • Density1,233.64/sq mi (476.12/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
13607
FIPS code36-01187
GNIS feature ID0942309
Websitewww.villageofalexandriabay.com

Alexandria Bay, New York Media

References

  1. "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
  2. 2.0 2.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Alexandria Bay village, New York". United States Census Bureau. Retrieved March 10, 2024.