Harcourt, Iowa
Harcourt is a city in Iowa in the United States. It is in Webster County.
 Location of Harcourt, Iowa | |
| Coordinates: 42°15′43″N 94°10′36″W / 42.26194°N 94.17667°WCoordinates: 42°15′43″N 94°10′36″W / 42.26194°N 94.17667°W | |
| Country |  United States |
| State |  Iowa |
| County | Webster |
| Area | |
| • Total | 0.6 sq mi (1.5 km2) |
| • Land | 0.6 sq mi (1.5 km2) |
| • Water | 0.0 sq mi (0.0 km2) |
| Elevation | 1,175 ft (358 m) |
| Population (2000) | |
| • Total | 340 |
| • Density | 592.5/sq mi (228.8/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 50544 |
| FIPS code | 19-34410 |
| GNIS feature ID | 0457242 |
Harcourt, Iowa Media
The population of Harcourt, Iowa from US census data
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