Petersburg, Indiana
Petersburg, Indiana is a city in Indiana in the United States. It is the county seat of Pike County.
 | |
 Location of Petersburg in Pike County, Indiana. | |
| Coordinates: 38°29′30″N 87°16′49″W / 38.49167°N 87.28028°WCoordinates: 38°29′30″N 87°16′49″W / 38.49167°N 87.28028°W | |
| Country | United States |
| State | Indiana |
| County | Pike |
| Township | Washington |
| Area | |
| • Total | 1.47 sq mi (3.81 km2) |
| • Land | 1.47 sq mi (3.80 km2) |
| • Water | 0.00 sq mi (0.00 km2) 0% |
| Elevation | 482 ft (147 m) |
| Population | |
| • Total | 2,304 |
| • Density | 1,569.48/sq mi (605.91/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 47567 |
| FIPS code | 18-59364[4] |
| GNIS feature ID | 449709 |
| Interstate Highways |  |
| Major State Roads |     |
| Website | http://www.petersburg.in.gov/ |
References
- ↑ 2020 U.S. Gazetteer FilesUnited States Census Bureau. Retrieved March 16, 2022.
- ↑ US Board on Geographic Names (October 25, 2007)United States Geological Survey. Retrieved January 31, 2008.
- ↑ Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Petersburg city, IndianaUnited States Census Bureau. Retrieved February 15, 2024.
- ↑ U.S. Census websiteUnited States Census Bureau. Retrieved January 31, 2008.