Solebury Township, Pennsylvania
Solebury Township is a township in Bucks County, Pennsylvania, United States. The population was 8,692 at the 2010 census.
Location of Solebury Township in Bucks County | |
| Coordinates: 40°23′00″N 74°59′49″W / 40.38333°N 74.99694°WCoordinates: 40°23′00″N 74°59′49″W / 40.38333°N 74.99694°W | |
| Country | United States |
| State | Pennsylvania |
| County | Bucks |
| Area | |
| • Total | 27.15 sq mi (70.3 km2) |
| • Land | 26.57 sq mi (68.8 km2) |
| • Water | 0.58 sq mi (1.5 km2) |
| Elevation | 279 ft (85 m) |
| Population (2010) | |
| • Total | 8,692 |
| • Estimate (2016)[2] | 8,599 |
| • Density | 320.15/sq mi (123.610/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| FIPS code | 42-017-71752 |
| Website | www |
Solebury Township, Pennsylvania Media
References
- ↑ "2016 U.S. Gazetteer Files". United States Census Bureau. Retrieved Aug 13, 2017.
- ↑ "Population and Housing Unit Estimates". Retrieved June 9, 2017.