Spring Hill, Florida

Spring Hill is a census-designated place (CDP) in Hernando County, Florida, United States. The population was 113,568 at the 2020 census.[2]

Spring Hill, Florida Gateway @ US 19.jpg
Location in Hernando County and the state of Florida
Location in Hernando County and the state of Florida
Coordinates: 28°28′44″N 82°32′52″W / 28.47889°N 82.54778°W / 28.47889; -82.54778Coordinates: 28°28′44″N 82°32′52″W / 28.47889°N 82.54778°W / 28.47889; -82.54778
CountryUnited States
StateFlorida
CountyHernando
Area
 • Total62.30 sq mi (161.36 km2)
 • Land59.92 sq mi (155.19 km2)
 • Water2.38 sq mi (6.17 km2)
Highest elevation
135 ft (41 m)
Lowest elevation
17 ft (5 m)
Population
 • Total113,568
 • Density1,895.39/sq mi (731.81/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP codes
34604-34610
FIPS code12-68350[3]
GNIS feature ID0294933[4]

Spring Hill, Florida Media

References

  1. "2022 U.S. Gazetteer Files: Florida". United States Census Bureau. Retrieved December 20, 2022.
  2. 2.0 2.1 "P1. Race – Spring Hill CDP, Florida: 2020 DEC Redistricting Data (PL 94-171)". U.S. Census Bureau. Retrieved December 20, 2022.
  3. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  4. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.