1896 United States presidential election

The 1896 United States presidential election was the 28th presidential election in the United States. It happened on Tuesday, November 3, 1896. Former Governor William McKinley, the Republican candidate, defeated Democrat William Jennings Bryan. The 1896 campaign happened during an economic depression called the Panic of 1893. The election is considered to mark the change from the "Third Party System" to the "Fourth Party System".[2]

1896 United States presidential election

← 1892 November 3, 1896 1900 →

447 members of the Electoral College
224 electoral votes needed to win
Turnout79.3%[1] Increase 4.6 pp
  William McKinley by Courtney Art Studio, 1896 (cropped).jpg William Jennings Bryan 2 (cropped).jpg
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Alliance
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
(Democratic, Silver)
Thomas E. Watson
(Populist)
Electoral vote 271 176
States carried 23 22
Popular vote 7,112,138 6,510,807
Percentage 51.0% 46.7%

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About this image
Presidential election results map. Red denotes those won by McKinley/Hobart, blue denotes states won by Bryan/Sewall and the Democratic/Populist ticket of Bryan/Watson. Numbers indicate the number of electoral votes allotted to each state.

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican


Although, McKinley's 1896 nomination was his first time securing the nomination, he had received 10+ delegates in every convention since 1888.

Candidates

Republican Party:

Democratic Party;

1896 United States Presidential Election Media

References

  1. "Voter Turnout in Presidential Elections". The American Presidency Project. UC Santa Barbara.
  2. Williams (2010)

Other websites