Albany, Wyoming
Albany is a census-designated place (CDP) in Albany County, Wyoming, United States. Its population was 55 at the 2010 census.
 Location in Albany County and the state of Wyoming. | |
| Coordinates: 41°10′48″N 106°6′52″W / 41.18000°N 106.11444°WCoordinates: 41°10′48″N 106°6′52″W / 41.18000°N 106.11444°W[1] | |
| Country | United States |
| State | Wyoming |
| County | Albany |
| Area | |
| • Total | 11.0 sq mi (28 km2) |
| • Land | 11.0 sq mi (28 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 8,327 ft (2,538 m) |
| Population | |
| • Total | 55 |
| • Density | 5.00/sq mi (1.931/km2) |
| Time zone | UTC-7 (Mountain (MST)) |
| • Summer (DST) | UTC-6 (MDT) |
| FIPS code | 56-00680[3] |
| GNIS feature ID | 1597700[4] |
References
- ↑ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23.
- ↑ "2010 City Population and Housing Occupancy Status". U.S. Census Bureau. Retrieved July 13, 2012.
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
- ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
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