Alexander, Iowa
Alexander is a city in Iowa in the United States.
 Location of Alexander, Iowa | |
| Coordinates: 42°48′17″N 93°28′39″W / 42.80472°N 93.47750°WCoordinates: 42°48′17″N 93°28′39″W / 42.80472°N 93.47750°W | |
| Country |  United States |
| State |  Iowa |
| County | Franklin |
| Area | |
| • Total | 4.27 sq mi (11.05 km2) |
| • Land | 4.27 sq mi (11.05 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 1,270 ft (387 m) |
| Population | |
| • Total | 164 |
| • Density | 38.43/sq mi (14.84/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 50420 |
| FIPS code | 19-01090 |
| GNIS feature ID | 0454123 |
Alexander, Iowa Media
The population of Alexander, Iowa from US census data
References
- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ↑ "Alexander city, Iowa". United States Census Bureau. Retrieved October 30, 2023.
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