Andrew, Iowa
Andrew is a city in Iowa in the United States.
 Location of Andrew, Iowa | |
| Coordinates: 42°09′15″N 90°35′30″W / 42.154059°N 90.591765°WCoordinates: 42°09′15″N 90°35′30″W / 42.154059°N 90.591765°W | |
| Country |  United States |
| State |  Iowa |
| County | Jackson |
| Incorporated | August 4, 1863 [1] |
| Area | |
| • Total | 0.25 sq mi (0.64 km2) |
| • Land | 0.25 sq mi (0.64 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 883 ft (269 m) |
| Population | |
| • Total | 380 |
| • Density | 1,532.26/sq mi (591.69/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 52030 |
| FIPS code | 19-02125 |
| GNIS feature ID | 0454187 |
Andrew, Iowa Media
The population of Andrew, Iowa from US census data
References
- ↑ List of Incorporated CitiesIowa Secretary of State. Retrieved 24 January 2020.
- ↑ 2020 U.S. Gazetteer FilesUnited States Census Bureau. Retrieved March 16, 2022.
- ↑ Andrew city, IowaUnited States Census Bureau. Retrieved November 3, 2023.
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