Conesville, Iowa
Conesville is a city in Iowa in the United States.
 Location of Conesville, Iowa | |
| Coordinates: 41°22′46″N 91°21′1″W / 41.37944°N 91.35028°WCoordinates: 41°22′46″N 91°21′1″W / 41.37944°N 91.35028°W | |
| Country |  United States |
| State |  Iowa |
| County | Muscatine |
| Area | |
| • Total | 0.36 sq mi (0.93 km2) |
| • Land | 0.36 sq mi (0.93 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 610 ft (186 m) |
| Population (2010) | |
| • Total | 432 |
| • Estimate (2019)[2] | 427 |
| • Density | 1,189.42/sq mi (459.82/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 52739 |
| FIPS code | 19-15645 |
| GNIS feature ID | 0455573 |
Conesville, Iowa Media
The population of Conesville, Iowa from US census data
References
- ↑ "2019 U.S. Gazetteer Files". United States Census Bureau. Retrieved July 17, 2020.
- ↑ "Population and Housing Unit Estimates". United States Census Bureau. May 24, 2020. Retrieved May 27, 2020.
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