Jefferson, Ohio
Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.[3] It is the county seat of Ashtabula County.[5]
 | |
 Location of Jefferson, Ohio | |
 Location of Jefferson in Ashtabula County | |
| Coordinates: 41°44′19″N 80°45′25″W / 41.73861°N 80.75694°WCoordinates: 41°44′19″N 80°45′25″W / 41.73861°N 80.75694°W | |
| Country | United States |
| State | Ohio |
| County | Ashtabula |
| Area | |
| • Total | 2.54 sq mi (6.57 km2) |
| • Land | 2.54 sq mi (6.57 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 961 ft (293 m) |
| Population | |
| • Total | 3,226 |
| • Density | 1,271.58/sq mi (491.04/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 44047 |
| FIPS code | 39-38500[4] |
| GNIS feature ID | 1042061[2] |
| Website | https://jeffersonohio.gov/ |
Jefferson, Ohio Media
Jefferson Town Hall, 27 E. Jefferson St. Jefferson
References
- ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
- ↑ 2.0 2.1 U.S. Geological Survey Geographic Names Information System: Jefferson, Ohio
- ↑ 3.0 3.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson village, Ohio". United States Census Bureau. Retrieved March 16, 2024.
- ↑ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ↑ National Association of Counties. "NACo County Explorer". Retrieved March 15, 2024.
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