Keota, Iowa
Keota is a city of Keokuk County in the state of Iowa in the United States.
 | |
 Location of Keota, Iowa | |
| Coordinates: 41°21′54″N 91°57′12″W / 41.36500°N 91.95333°WCoordinates: 41°21′54″N 91°57′12″W / 41.36500°N 91.95333°W | |
| Country |  United States |
| State |  Iowa |
| Counties | Keokuk, Washington |
| Townships | Lafayette, Seventy-Six |
| Area | |
| • Total | 0.77 sq mi (2.00 km2) |
| • Land | 0.77 sq mi (2.00 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 801 ft (244 m) |
| Population | |
| • Total | 897 |
| • Density | 1,160.41/sq mi (447.84/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 52248 |
| FIPS code | 19-40980 |
| GNIS feature ID | 2395518[2] |
| Website | www |
References
- ↑ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ↑ 2.0 2.1 U.S. Geological Survey Geographic Names Information System: Keota, Iowa
- ↑ "Keota city, Iowa". United States Census Bureau. Retrieved November 7, 2023.
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