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# Lorentz transformation

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$x'=\frac{x-vt}{\sqrt{1-\frac{v^2}{c^2}}}$ , $y'=y$ , $z'=z$ , $t'=\frac{t-\frac{vx}{c^2}}{\sqrt{1-\frac{v^2}{c^2}}}$
where $x'$represents the new x co-ordinate, $v$ represents the velocity of the other reference frame, $t$ representing time, and $c$ the speed of light.
On a Cartesian coordinate system, with the vertical axis being time (t), the horizontal axis being position in space along one axis (x), the gradients represent velocity (shallower gradient resulting in a greater velocity). If the speed of light is set as a 45° or 1:1 gradient, Lorentz transformations can rotate and squeeze other gradients while keeping certain gradients, like a 1:1 gradient constant. Points undergoing a Lorentz transformations on such a plane will be transformed along lines corresponding to $t^2-x^2=n^2$ where n is some number Points undergoing a Lorentz transformation follow the green, conjugate hyperbola, where the vertical axis represents time, $y^2-x^2=n^2$