Panama, Iowa
Panama is a city in Shelby County, Iowa, United States. The population was 221 at the 2010 census.
 Location of Panama, Iowa | |
| Coordinates: 41°43′36″N 95°28′27″W / 41.72667°N 95.47417°WCoordinates: 41°43′36″N 95°28′27″W / 41.72667°N 95.47417°W | |
| Country |  United States |
| State |  Iowa |
| County | Shelby |
| Area | |
| • Total | 0.29 sq mi (0.75 km2) |
| • Land | 0.29 sq mi (0.75 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 1,266 ft (386 m) |
| Population | |
| • Total | 221 |
| • Density | 762.1/sq mi (294.2/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP codes | 51562, 51578 |
| FIPS code | 19-61275 |
| GNIS feature ID | 0460009 |
References
- ↑ "US Gazetteer files 2010". United States Census Bureau. Retrieved 2012-05-11.
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2012-05-11.
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