Sandy, Utah

Sandy is a city in the Salt Lake City metropolitan area, located in Salt Lake County, Utah, United States. The population of Sandy was 96,904 at the 2020 census.[2]

Sandy, Utah city hall.jpg
Location in Salt Lake County and the state of Utah.
Location in Salt Lake County and the state of Utah.
Coordinates: 40°34′21″N 111°51′35″W / 40.57250°N 111.85972°W / 40.57250; -111.85972Coordinates: 40°34′21″N 111°51′35″W / 40.57250°N 111.85972°W / 40.57250; -111.85972
CountryUnited States
StateUtah
CountySalt Lake
Founded1871
Incorporated1893
Area
 • Total24.11 sq mi (62.44 km2)
 • Land24.10 sq mi (62.41 km2)
 • Water0.01 sq mi (0.03 km2)
Elevation
4,450 ft (1,356 m)
Population
 • Total96,904
 • Density4,019.2/sq mi (1,551.95/km2)
Time zoneUTC−7 (MST)
 • Summer (DST)UTC−6 (MDT)
ZIP codes
84070, 84090-84094
FIPS code49-67440[3]
Websitewww.sandy.utah.gov

Sandy, Utah Media

References

  1. "2019 U.S. Gazetteer Files". United States Census Bureau. Retrieved August 7, 2020.
  2. 2.0 2.1 "Sandy city, Utah". United States Census Bureau. Retrieved July 27, 2023.
  3. "Profile of General Population and Housing Characteristics: 2010". United States Census Bureau. 2010. Archived from the original on 13 February 2020. Retrieved 28 May 2014.