Springville, Iowa
Springville is a city in Iowa in the United States.
 Location of Springville, Iowa | |
| Coordinates: 42°3′25″N 91°26′39″W / 42.05694°N 91.44417°WCoordinates: 42°3′25″N 91°26′39″W / 42.05694°N 91.44417°W | |
| Country |  United States |
| State |  Iowa |
| County | Linn |
| Area | |
| • Total | 0.72 sq mi (1.86 km2) |
| • Land | 0.71 sq mi (1.85 km2) |
| • Water | 0.00 sq mi (0.01 km2) |
| Elevation | 833 ft (254 m) |
| Population (2010) | |
| • Total | 1,074 |
| • Estimate (2019)[2] | 1,137 |
| • Density | 1,592.44/sq mi (614.62/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 52336 |
| FIPS code | 19-74775 |
| GNIS feature ID | 0461923 |
| Website | www |
References
- ↑ "2019 U.S. Gazetteer Files". United States Census Bureau. Retrieved July 17, 2020.
- ↑ "Population and Housing Unit Estimates". United States Census Bureau. May 24, 2020. Retrieved May 27, 2020.
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