Martins Ferry, Ohio
Martins Ferry is a city in Belmont County, Ohio, United States, on the Ohio River. It is the largest city in Belmont County. 6,915 people lived there as of the 2010 census.
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Coordinates: 40°5′57″N 80°43′31″W / 40.09917°N 80.72528°WCoordinates: 40°5′57″N 80°43′31″W / 40.09917°N 80.72528°W | |
Country | United States |
State | Ohio |
County | Belmont |
Area | |
• Total | 2.33 sq mi (6.03 km2) |
• Land | 2.33 sq mi (6.03 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 709 ft (216 m) |
Population (2010) | |
• Total | 6,915 |
• Estimate (2012[2]) | 6,831 |
• Density | 2,967.8/sq mi (1,145.9/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 43935 |
FIPS code | 39-48104[3] |
GNIS feature ID | 1061478[1] |
Website | http://www.martinsferry.org/ |
Martins Ferry is part of the Wheeling metropolitan area.
Martins Ferry, Ohio Media
References
- ↑ 1.0 1.1 "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- ↑ "Population Estimates". United States Census Bureau. Archived from the original on June 17, 2013. Retrieved 2013-06-17.
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.