Martins Ferry, Ohio

Martins Ferry is a city in Belmont County, Ohio, United States, on the Ohio River. It is the largest city in Belmont County. 6,915 people lived there as of the 2010 census.

Fourth from Hanover, Martins Ferry.jpg
 
Location of Martins Ferry, Ohio
Location of Martins Ferry, Ohio
Location of Martins Ferry in Belmont County
Location of Martins Ferry in Belmont County
Coordinates: 40°5′57″N 80°43′31″W / 40.09917°N 80.72528°W / 40.09917; -80.72528Coordinates: 40°5′57″N 80°43′31″W / 40.09917°N 80.72528°W / 40.09917; -80.72528
CountryUnited States
StateOhio
CountyBelmont
Area
 • Total2.33 sq mi (6.03 km2)
 • Land2.33 sq mi (6.03 km2)
 • Water0 sq mi (0 km2)
Elevation709 ft (216 m)
Population
 (2010)
 • Total6,915
 • Estimate 
(2012[2])
6,831
 • Density2,967.8/sq mi (1,145.9/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
43935
FIPS code39-48104[3]
GNIS feature ID1061478[1]
Websitehttp://www.martinsferry.org/

Martins Ferry is part of the Wheeling metropolitan area.

Martins Ferry, Ohio Media

References

  1. 1.0 1.1 "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "Population Estimates". United States Census Bureau. Archived from the original on June 17, 2013. Retrieved 2013-06-17.
  3. "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.