Romulus, New York
Romulus is a town in Seneca County, New York, United States. The population was 3,203 at the 2020 census.[3]
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| Coordinates: 42°43′19″N 76°50′26″W / 42.72194°N 76.84056°W | |
| Country | United States |
| State | New York |
| County | Seneca |
| Settled | 1789 |
| Established | March 5, 1794[1] |
| Area | |
| • Total | 51.38 sq mi (133.08 km2) |
| • Land | 37.79 sq mi (97.88 km2) |
| • Water | 13.59 sq mi (35.20 km2) |
| Elevation | 758 ft (231 m) |
| Population | |
| • Total | 3,203 |
| • Density | 84.75/sq mi (32.72/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 14541 |
| FIPS code | 36-63440 |
| GNIS feature ID | 0979431 |
| Website | http://www.romulustown.com/ |
References
- ↑ Template:Cite Q
- ↑ 2020 U.S. Gazetteer FilesUnited States Census Bureau. Retrieved March 8, 2024.
- ↑ 3.0 3.1 Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Romulus town, Seneca County, New YorkUnited States Census Bureau. Retrieved March 8, 2024.
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