Sandusky, Ohio

Sandusky /sænˈdʌsk/ is a city in the U.S. state of Ohio and the county seat of Erie County.[6]

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Coordinates: 41°26′48″N 82°42′33″W / 41.44667°N 82.70917°W / 41.44667; -82.70917Coordinates: 41°26′48″N 82°42′33″W / 41.44667°N 82.70917°W / 41.44667; -82.70917
Country United States
StateFile:Flag of Ohio.svg Ohio
CountyErie
Founded1818
Area
 • City21.83 sq mi (56.53 km2)
 • Land9.63 sq mi (24.96 km2)
 • Water12.19 sq mi (31.58 km2)
Elevation
597 ft (182 m)
Population
 • City25,095
 • Density2,604.57/sq mi (1,005.58/km2)
 • Metro
115,986
Time zoneUTC−05:00 (EST)
 • Summer (DST)UTC−04:00 (EDT)
ZIP Codes
44870–44871
FIPS code39-70380[3]
GNIS feature ID1076832[4]
Websitewww.ci.sandusky.oh.us

According to 2020 census, the city had a population of 25,095.[2]

In 2011, Sandusky was ranked No. 1 by Forbes as the "Best Place to Live Cheaply" in the United States.[7]

Sandusky, Ohio Media

References

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  6. Lua error in Module:Citation/CS1/Utilities at line 38: bad argument #1 to 'ipairs' (table expected, got nil).
  7. Fisher, Daniel (2011-08-10). "Best Places To Live Cheaply". Forbes. https://www.forbes.com/sites/danielfisher/2011/08/10/best-places-to-live-cheaply-2/.