Warrensville Heights, Ohio
Warrensville Heights is a city located in Cuyahoga County, Ohio, United States. It is an East Side suburb of Cleveland. The population was 13,542 at the 2010 U.S. Census.
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 Location in Cuyahoga County and the state of Ohio | |
.svg) Location of Ohio in the United States | |
| Coordinates: 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°WCoordinates: 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°W | |
| Country | United States |
| State | Ohio |
| County | Cuyahoga |
| Village incorporated | 1927 [1] |
| Incorporated | 1960 [1] |
| Government | |
| • Type | Mayor-council |
| • Mayor | Brad Sellers (D) |
| Area | |
| • Total | 4.14 sq mi (10.72 km2) |
| • Land | 4.13 sq mi (10.70 km2) |
| • Water | 0.01 sq mi (0.03 km2) 0.24% |
| Elevation | 1,037 ft (316 m) |
| Population (2010) | |
| • Total | 13,542 |
| • Estimate (2018[2]) | 13,216 |
| • Density | 3,278.9/sq mi (1,266.0/km2) |
| census | |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| Zip code | 44122, 44128 |
| FIPS code | 39-80990[3] |
| GNIS feature ID | 1047579[4] |
| Website | http://www.cityofwarrensville.com/ |
References
- ↑ 1.0 1.1 http://www.cityofwarrensville.com/general.htm Archived 2016-03-03 at the Wayback Machine Retrieved 30 December 2006.
- ↑ "Population and Housing Unit Estimates". Retrieved June 9, 2019.
- ↑ "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
- ↑ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
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