Warrensville Heights, Ohio
Warrensville Heights is a city located in Cuyahoga County, Ohio, United States. It is an East Side suburb of Cleveland. The population was 13,789 at the 2020 U.S. Census.[4]
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 Location in Cuyahoga County and the state of Ohio | |
| Coordinates: 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°WCoordinates: 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°W | |
| Country | United States |
| State | Ohio |
| County | Cuyahoga |
| Village incorporated | 1927 [1] |
| Incorporated | 1960 [1] |
| Government | |
| • Type | Mayor-council |
| Area | |
| • Total | 4.13 sq mi (10.69 km2) |
| • Land | 4.12 sq mi (10.68 km2) |
| • Water | 0.01 sq mi (0.01 km2) 0.24% |
| Elevation | 1,037 ft (316 m) |
| Population | |
| • Total | 13,789 |
| • Density | 3,344.41/sq mi (1,291.27/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| Zip code | 44122, 44128 |
| FIPS code | 39-80990[5] |
| GNIS feature ID | 1047579[3] |
| Website | www |
References
- ↑ 1.0 1.1 "Welcome to Warrensville Heights! Live, explore, visit and have fun in the Friendly City". www.cityofwarrensville.com. Archived from the original on February 14, 2004. Retrieved March 9, 2023.
- ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
- ↑ 3.0 3.1 U.S. Geological Survey Geographic Names Information System: Warrensville Heights, Ohio
- ↑ 4.0 4.1 "QuickFacts: Warrensville Heights city, Ohio". United States Census Bureau. Retrieved March 15, 2024.
- ↑ "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
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