2020 United States presidential election in Indiana
The 2020 United States presidential election in Indiana was held on Tuesday, November 3, 2020, as part of the 2020 United States presidential election.[3] Incumbent President Donald Trump, and running mate Vice President Mike Pence had won 11 electoral votes in the Electoral College.[4]
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Turnout | 61.37% [1] | |||||||||||||||||||||||||
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{| cellspacing="0" cellpadding="0" class="" style="background-color: transparent; width: 100%"
| width="50%" align="left" valign="top" | Trump 40–50% 50–60% 60–70% 70–80% 80–90% 90–100% | width="50%" align="left" valign="top" | Biden 40–50% 50–60% 60–70% 70–80% 80–90% 90–100% | width="33.33%" align="left" valign="top" | Tie/No Data |} | ||||||||||||||||||||||||||
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References
- ↑ "Voter turnout in United States elections". Ballotpedia. Retrieved 2022-08-03.
- ↑ "Indiana Election Results 2020". The New York Times. November 3, 2020. https://www.nytimes.com/interactive/2020/11/03/us/elections/results-indiana.html. Retrieved November 5, 2020.
- ↑ Kelly, Ben (August 13, 2018). "US elections key dates: When are the 2018 midterms and the 2020 presidential campaign?". The Independent. https://www.independent.co.uk/news/world/americas/us-elections-key-dates-midterms-2020-presidential-house-congress-senate-a8472821.html. Retrieved January 3, 2019.
- ↑
2020 United States Presidential Election In Indiana Media
"Distribution of Electoral Votes". National Archives and Records Administration. Retrieved January 3, 2019.