1884 United States presidential election

The 1884 United States presidential election was the 25th election in the history of the United States. It occurred on November 4, 1884. This election was between Governor Grover Cleveland of New York and former Secretary of State James G. Blaine of Maine. Cleveland won the election with 219 electoral votes, while Blaine got only 182 electoral votes.

1884 United States presidential election

← 1880 November 4, 1884 1888 →

401 members of the Electoral College
201 electoral votes needed to win
Turnout77.5%[1] Decrease 0.5 pp
  StephenGroverCleveland.jpg Unsuccessful 1884.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 219 182
States carried 20 18
Popular vote 4,914,482 4,856,905
Percentage 48.8% 48.3%

ElectoralCollege1884.svg
Presidential election results map. Blue denotes those won by Cleveland/Hendricks, red denotes states won by Blaine/Logan. Numbers indicate the number of electoral votes allotted to each state.

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

Candidates:

Republican Party:

Presidential:

Declined to Contest:

Vice-Presidential:

  • Thomas A. Hendricks, Former Governor of Indiana (1873-1877) (Vice-Presidential Nominee) (1876 Democratic Vice-Presidential Nominee)

Democratic Party:

Withdrawn Candidates:

1884 United States Presidential Election Media

References

  1. "Voter Turnout in Presidential Elections". The American Presidency Project. UC Santa Barbara.